Coding help

[Aruffell]

I have a site (index.php) and have made a table in it that i wish to open other files (1.php/2.php etc...)

If they don't exist i want it to open main.php.

I know there is an includes string to use with file_exists but can't for the life of me remember it.

Can anyone help?

Andy

 

[Sic]

there's a couple of ways to do it, personally i'd use the php $_GET so that you can differentiate between main and tabled views.

//get the page that you want from the url
$view = $_GET['view'];

if ($view = "table"){
//table.php needs to include your formatted includes for each row on the table
include ("table.php");
}else{
include ("main.php");
}

then to view the table, it will be visible on www.yourdomain.com/index.php?view=table so link to it that way. that'll work, but it's not what you asked for!

 

[Beansprout]

Change:

if ($view = "table"){

To:

if ($view == "table"){

 

[Sic]

oops

 

[Dj_Jestar]

List the pages available to the application in an array:

<?php

$pages = array('1.php', '2.php', '3.php', 'etc.');

?>

Then use a page id, similar to what Sic has suggested, which I'll demonstrate as the array key for $pages, and validate it:

<?php

$pages = array('1.php', '2.php', '3.php', 'etc.');

if (array_key_exists($_GET['pageid'], $pages)) {
    //pageid is valid input..
    if (file_exists($pages[$_GET['pageid']])) {
        //page exists
        include_once $pages[$_GET['pageid']];
    } else {
        //page does not exist..
        include_once 'main.php';
    }
} else {
    //pageid is not valid input..
    die ('Invalid pageid.');
}

?>

This is more secure than stating the filename in the URI.

HTH